在单节点服务器上，可以同步按行执行命令文件test.sh，test.sh里面有5,000行命令，先串联250行再并行提交20次，相当于20个线程，脚本如下：parallel.sh
#!/bin/bash
START=1
PER_TASK=250
for ((count=1; count<=20; count++));do
END=${PER_TASK}*count
for(( i=$START; i<=$END; i++ ));do
`sed -n "$i"p test.sh`
done &
START=$START+${PER_TASK}
done
nohup bash parallel.sh &
注意这里很快就done了，只是完成了sed命令，后台还在进行内部命令并没有完成，不要注意反复提交！！！
&在第二个for外面是串联，在第一个for里面则是并行
在集群服务器上，例如用Slurm调用作业资源系统的，多节点多线程运行某个作业任务，脚本如下：
#!/bin/bash
#SBATCH -J codeml_array
#SBATCH -p a05208har3
#SBATCH –array=1-5
#SBATCH –ntasks=1
#SBATCH –cpus-per-task=4
#SBATCH –output=Array.%A_%a.log
# bash codeml.sh #Job1
pwd; hostname; date
#Set the number of runs that each SLURM task should do
PER_TASK=100
# Calculate the starting and ending values for this task based
# on the SLURM task and the number of runs per task.
START_NUM=$(( ($SLURM_ARRAY_TASK_ID – 1) * $PER_TASK + 1 ))
END_NUM=$(( $SLURM_ARRAY_TASK_ID * $PER_TASK ))
# Print the task and run range
echo This is task $SLURM_ARRAY_TASK_ID, which will do runs $START_NUM to $END_NUM
# Run the loop of runs for this task.
for (( run=$START_NUM; run<=END_NUM; run++ )); do
echo This is SLURM task $SLURM_ARRAY_TASK_ID, run number $run
#Do your stuff here
`sed -n "$run"p codeml.sh`
done
date
原文链接：https://blog.csdn.net/weixin_34520360/article/details/119441023
原创文章，作者：优速盾-小U，如若转载，请注明出处：https://www.cdnb.net/bbs/archives/5875
